Observe the three columns in which column-1 Elements, Column-2 Property (Compare in given elements), while column-3 Aqueous solution of element salts show colours.
Column-1 | Column-2 | Column-3 | |||
(I) | Fe | (i) | Highest IInd I.E. | (P) | Light pink |
(II) | Ni | (ii) | M in M(CO)4 is sp3 hybridization | (Q) | Green |
(III) | Cu | (iii) | (+3) oxidation state is more paramagnetic than (+2) | (R) | Colour less |
(IV) | Mn | (iv) | Shows +7 oxidation state (highest) | (S) | Green Pale |
(i) Which combination is correct :
Text Solution
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(i) Ni ; Ni(CO) 4 is tetraderal (sp 3 )
NiCl 2 ·4H 2 O = green
Cu ; Cu 2 Cl 2 colour less
Cu +1 = 3d 10
Highest II nd I.E.
Mn : Mn - +7 oxidation number
MnCl 2 ·4H 2 O - light pink
(ii) . Fe, Fe +3 = 3d 5 4s 0 No. of unpaired electron = 5
Fe +2 = 3d 6 4s 0 No. of unpaired electron = 4
FeSO 4 ·7H 2 O = Pale Green
(iii) Ni(CO) 4 , NiCl 4 ·4H 2 O = green
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